Given an array of integers arr, and three integers a, b and c. You need to find the number of good triplets.
A triplet (arr[i], arr[j], arr[k]) is good if the following conditions are true:
0 <= i < j < k < arr.length
|arr[i] - arr[j]| <= a
|arr[j] - arr[k]| <= b
|arr[i] - arr[k]| <= c
Where |x| denotes the absolute value of x.
Return the number of good triplets.
Example 1:
Input: arr = [3,0,1,1,9,7], a = 7, b = 2, c = 3
Output: 4
Explanation: There are 4 good triplets: [(3,0,1), (3,0,1), (3,1,1), (0,1,1)].
Example 2:
InInput: arr = [1,1,2,2,3], a = 0, b = 0, c = 1
Output: 0
Explanation: No triplet satisfies all conditions.
var countGoodTriplets = function(arr, a, b, c) {
let n=0
for(let i=0; i<arr.length-2; i++)
{
for(let j=i+1; j<arr.length-1; j++)
{
if(Math.abs(arr[i] - arr[j]) > a) continue
for(let k=j+1; k<arr.length; k++)
{
if(Math.abs(arr[j] - arr[k]) > b) continue
if(Math.abs(arr[i] - arr[k]) > c) continue
n++
}
}
}
return n
};